0=3(y-6)+-9

Solution for 0=3(y-6)+-9 equation:

0=3(y-6)+-9

We move all terms to the left:

0-(3(y-6)+-9)=0

We add all the numbers together, and all the variables

-(3(y-6)+-9)=0

We use the square of the difference formula

-(3(y-6)-9)=0


We calculate terms in parentheses: -(3(y-6)-9), so:

3(y-6)-9

We multiply parentheses

3y-18-9

We add all the numbers together, and all the variables

3y-27

Back to the equation:

-(3y-27)


We get rid of parentheses

-3y+27=0

We move all terms containing y to the left, all other terms to the right

-3y=-27

y=-27/-3

y=+9