0=3-d-(d+1)

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Solution for 0=3-d-(d+1) equation: 



0=3-d-(d+1)

We move all terms to the left:

0-(3-d-(d+1))=0

We add all the numbers together, and all the variables

-(3-d-(d+1))=0



We calculate terms in parentheses: -(3-d-(d+1)), so:

3-d-(d+1)

determiningTheFunctionDomain
-d-(d+1)+3

We add all the numbers together, and all the variables

-1d-(d+1)+3

We get rid of parentheses

-1d-d-1+3

We add all the numbers together, and all the variables

-2d+2

Back to the equation:

-(-2d+2)



We get rid of parentheses

2d-2=0

We move all terms containing d to the left, all other terms to the right

2d=2

d=2/2

d=1

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