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0=32+2(m-6)
We move all terms to the left:
0-(32+2(m-6))=0
We add all the numbers together, and all the variables
-(32+2(m-6))=0
We calculate terms in parentheses: -(32+2(m-6)), so:We get rid of parentheses
32+2(m-6)
determiningTheFunctionDomain 2(m-6)+32
We multiply parentheses
2m-12+32
We add all the numbers together, and all the variables
2m+20
Back to the equation:
-(2m+20)
-2m-20=0
We move all terms containing m to the left, all other terms to the right
-2m=20
m=20/-2
m=-10
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