0=36x2-60x+11

Solution for 0=36x2-60x+11 equation:

0=36x^2-60x+11

We move all terms to the left:

0-(36x^2-60x+11)=0

We add all the numbers together, and all the variables

-(36x^2-60x+11)=0

We get rid of parentheses

-36x^2+60x-11=0

a = -36; b = 60; c = -11;
Δ = b2-4ac
Δ = 602-4·(-36)·(-11)
Δ = 2016
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2016}=\sqrt{144*14}=\sqrt{144}*\sqrt{14}=12\sqrt{14}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-12\sqrt{14}}{2*-36}=\frac{-60-12\sqrt{14}}{-72}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+12\sqrt{14}}{2*-36}=\frac{-60+12\sqrt{14}}{-72}
$