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0=3h^2-11h-90
We move all terms to the left:
0-(3h^2-11h-90)=0
We add all the numbers together, and all the variables
-(3h^2-11h-90)=0
We get rid of parentheses
-3h^2+11h+90=0
a = -3; b = 11; c = +90;
Δ = b2-4ac
Δ = 112-4·(-3)·90
Δ = 1201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{1201}}{2*-3}=\frac{-11-\sqrt{1201}}{-6} $$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{1201}}{2*-3}=\frac{-11+\sqrt{1201}}{-6} $
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