0=3p(p-9)

Solution for 0=3p(p-9) equation:

0=3p(p-9)

We move all terms to the left:

0-(3p(p-9))=0

We add all the numbers together, and all the variables

-(3p(p-9))=0


We calculate terms in parentheses: -(3p(p-9)), so:

3p(p-9)

We multiply parentheses

3p^2-27p

Back to the equation:

-(3p^2-27p)


We get rid of parentheses

-3p^2+27p=0

a = -3; b = 27; c = 0;
Δ = b2-4ac
Δ = 272-4·(-3)·0
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-27}{2*-3}=\frac{-54}{-6}
=+9
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+27}{2*-3}=\frac{0}{-6}
=0
$