0=4(0.5x-8)(8-40x)

Solution for 0=4(0.5x-8)(8-40x) equation:

0=4(0.5x-8)(8-40x)

We move all terms to the left:

0-(4(0.5x-8)(8-40x))=0

We add all the numbers together, and all the variables

-(4(0.5x-8)(-40x+8))+0=0

We add all the numbers together, and all the variables

-(4(0.5x-8)(-40x+8))=0

We multiply parentheses ..

-(4(+0x^2+0x+320x-64))=0


We calculate terms in parentheses: -(4(+0x^2+0x+320x-64)), so:

4(+0x^2+0x+320x-64)

We multiply parentheses

0x^2+0x+1280x-256

We add all the numbers together, and all the variables

x^2+1281x-256

Back to the equation:

-(x^2+1281x-256)


We get rid of parentheses

-x^2-1281x+256=0

We add all the numbers together, and all the variables

-1x^2-1281x+256=0

a = -1; b = -1281; c = +256;
Δ = b2-4ac
Δ = -12812-4·(-1)·256
Δ = 1641985
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1281)-\sqrt{1641985}}{2*-1}=\frac{1281-\sqrt{1641985}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1281)+\sqrt{1641985}}{2*-1}=\frac{1281+\sqrt{1641985}}{-2}
$