0=4(2y-4y)+2y-2

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Solution for 0=4(2y-4y)+2y-2 equation: 



0=4(2y-4y)+2y-2

We move all terms to the left:

0-(4(2y-4y)+2y-2)=0

We add all the numbers together, and all the variables

-(4(-2y)+2y-2)+0=0

We add all the numbers together, and all the variables

-(4(-2y)+2y-2)=0



We calculate terms in parentheses: -(4(-2y)+2y-2), so:

4(-2y)+2y-2

We add all the numbers together, and all the variables

2y+4(-2y)-2

We multiply parentheses

2y-8y-2

We add all the numbers together, and all the variables

-6y-2

Back to the equation:

-(-6y-2)



We get rid of parentheses

6y+2=0

We move all terms containing y to the left, all other terms to the right

6y=-2

y=-2/6

y=-1/3

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