0=4(z-3)+5-2z

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Solution for 0=4(z-3)+5-2z equation: 



0=4(z-3)+5-2z

We move all terms to the left:

0-(4(z-3)+5-2z)=0

We add all the numbers together, and all the variables

-(4(z-3)+5-2z)=0



We calculate terms in parentheses: -(4(z-3)+5-2z), so:

4(z-3)+5-2z

determiningTheFunctionDomain
4(z-3)-2z+5

We add all the numbers together, and all the variables

-2z+4(z-3)+5

We multiply parentheses

-2z+4z-12+5

We add all the numbers together, and all the variables

2z-7

Back to the equation:

-(2z-7)



We get rid of parentheses

-2z+7=0

We move all terms containing z to the left, all other terms to the right

-2z=-7

z=-7/-2

z=3+1/2

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