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0=450-18x^2
We move all terms to the left:
0-(450-18x^2)=0
We add all the numbers together, and all the variables
-(450-18x^2)=0
We get rid of parentheses
18x^2-450=0
a = 18; b = 0; c = -450;
Δ = b2-4ac
Δ = 02-4·18·(-450)
Δ = 32400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{32400}=180$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-180}{2*18}=\frac{-180}{36} =-5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+180}{2*18}=\frac{180}{36} =5 $
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