0=4t2+15t+10

Solution for 0=4t2+15t+10 equation:

0=4t^2+15t+10

We move all terms to the left:

0-(4t^2+15t+10)=0

We add all the numbers together, and all the variables

-(4t^2+15t+10)=0

We get rid of parentheses

-4t^2-15t-10=0

a = -4; b = -15; c = -10;
Δ = b2-4ac
Δ = -152-4·(-4)·(-10)
Δ = 65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{65}}{2*-4}=\frac{15-\sqrt{65}}{-8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{65}}{2*-4}=\frac{15+\sqrt{65}}{-8}
$