0=4x(2x-10)

Solution for 0=4x(2x-10) equation:

0=4x(2x-10)

We move all terms to the left:

0-(4x(2x-10))=0

We add all the numbers together, and all the variables

-(4x(2x-10))=0


We calculate terms in parentheses: -(4x(2x-10)), so:

4x(2x-10)

We multiply parentheses

8x^2-40x

Back to the equation:

-(8x^2-40x)


We get rid of parentheses

-8x^2+40x=0

a = -8; b = 40; c = 0;
Δ = b2-4ac
Δ = 402-4·(-8)·0
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-40}{2*-8}=\frac{-80}{-16}
=+5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+40}{2*-8}=\frac{0}{-16}
=0
$