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0=4x(3x-15)
We move all terms to the left:
0-(4x(3x-15))=0
We add all the numbers together, and all the variables
-(4x(3x-15))=0
We calculate terms in parentheses: -(4x(3x-15)), so:We get rid of parentheses
4x(3x-15)
We multiply parentheses
12x^2-60x
Back to the equation:
-(12x^2-60x)
-12x^2+60x=0
a = -12; b = 60; c = 0;
Δ = b2-4ac
Δ = 602-4·(-12)·0
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3600}=60$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-60}{2*-12}=\frac{-120}{-24} =+5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+60}{2*-12}=\frac{0}{-24} =0 $
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