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0=4x^2+12x+9
We move all terms to the left:
0-(4x^2+12x+9)=0
We add all the numbers together, and all the variables
-(4x^2+12x+9)=0
We get rid of parentheses
-4x^2-12x-9=0
a = -4; b = -12; c = -9;
Δ = b2-4ac
Δ = -122-4·(-4)·(-9)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{12}{-8}=-1+1/2$
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