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0=4z+8z^2
We move all terms to the left:
0-(4z+8z^2)=0
We add all the numbers together, and all the variables
-(4z+8z^2)=0
We get rid of parentheses
-8z^2-4z=0
a = -8; b = -4; c = 0;
Δ = b2-4ac
Δ = -42-4·(-8)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4}{2*-8}=\frac{0}{-16} =0 $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4}{2*-8}=\frac{8}{-16} =-1/2 $
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