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0=5-(2x-17)x=
We move all terms to the left:
0-(5-(2x-17)x)=0
We add all the numbers together, and all the variables
-(5-(2x-17)x)=0
We calculate terms in parentheses: -(5-(2x-17)x), so:We get rid of parentheses
5-(2x-17)x
determiningTheFunctionDomain -(2x-17)x+5
We multiply parentheses
-2x^2+17x+5
Back to the equation:
-(-2x^2+17x+5)
2x^2-17x-5=0
a = 2; b = -17; c = -5;
Δ = b2-4ac
Δ = -172-4·2·(-5)
Δ = 329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-\sqrt{329}}{2*2}=\frac{17-\sqrt{329}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+\sqrt{329}}{2*2}=\frac{17+\sqrt{329}}{4} $
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