0=5-sin(2x)-4*cos(x)

Solution for 0=5-sin(2x)-4*cos(x) equation:

Simplifying
0 = 5 + -1sin(2x) + -4cos(x)

Remove parenthesis around (2x)
0 = 5 + -1ins * 2x + -4cos(x)

Reorder the terms for easier multiplication:
0 = 5 + -1 * 2ins * x + -4cos(x)

Multiply -1 * 2
0 = 5 + -2ins * x + -4cos(x)

Multiply ins * x
0 = 5 + -2insx + -4cos(x)

Multiply cos * x
0 = 5 + -2insx + -4cosx

Reorder the terms:
0 = 5 + -4cosx + -2insx

Solving
0 = 5 + -4cosx + -2insx

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '4cosx' to each side of the equation.
0 + 4cosx = 5 + -4cosx + 4cosx + -2insx
Remove the zero:
4cosx = 5 + -4cosx + 4cosx + -2insx

Combine like terms: -4cosx + 4cosx = 0
4cosx = 5 + 0 + -2insx
4cosx = 5 + -2insx

Divide each side by '4osx'.
c = 1.25o-1s-1x-1 + -0.5ino-1

Simplifying
c = 1.25o-1s-1x-1 + -0.5ino-1

Reorder the terms:
c = -0.5ino-1 + 1.25o-1s-1x-1