0=5x2+26x+24

Solution for 0=5x2+26x+24 equation:

0=5x^2+26x+24

We move all terms to the left:

0-(5x^2+26x+24)=0

We add all the numbers together, and all the variables

-(5x^2+26x+24)=0

We get rid of parentheses

-5x^2-26x-24=0

a = -5; b = -26; c = -24;
Δ = b2-4ac
Δ = -262-4·(-5)·(-24)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-14}{2*-5}=\frac{12}{-10}
=-1+1/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+14}{2*-5}=\frac{40}{-10}
=-4
$