0=6x2+13x+-5/(3x+-1)

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Solution for 0=6x2+13x+-5/(3x+-1) equation: 



0=6x^2+13x+-5/(3x+-1)

We move all terms to the left:

0-(6x^2+13x+-5/(3x+-1))=0



Domain of the equation: (3x+-1))!=0

x∈R



We add all the numbers together, and all the variables

-(6x^2+13x+-5/(3x-1))+0=0

We add all the numbers together, and all the variables

-(6x^2+13x+-5/(3x-1))=0

We use the square of the difference formula

-(6x^2+13x-5/(3x-1))=0

We multiply all the terms by the denominator


-(6x^2+13x-5=0

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