0=7(1-3a)-6(1+5a)

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Solution for 0=7(1-3a)-6(1+5a) equation: 



0=7(1-3a)-6(1+5a)

We move all terms to the left:

0-(7(1-3a)-6(1+5a))=0

We add all the numbers together, and all the variables

-(7(-3a+1)-6(5a+1))+0=0

We add all the numbers together, and all the variables

-(7(-3a+1)-6(5a+1))=0



We calculate terms in parentheses: -(7(-3a+1)-6(5a+1)), so:

7(-3a+1)-6(5a+1)

We multiply parentheses

-21a-30a+7-6

We add all the numbers together, and all the variables

-51a+1

Back to the equation:

-(-51a+1)



We get rid of parentheses

51a-1=0

We move all terms containing a to the left, all other terms to the right

51a=1

a=1/51

a=1/51

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