0=740+32(n-10)

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Solution for 0=740+32(n-10) equation: 



0=740+32(n-10)

We move all terms to the left:

0-(740+32(n-10))=0

We add all the numbers together, and all the variables

-(740+32(n-10))=0



We calculate terms in parentheses: -(740+32(n-10)), so:

740+32(n-10)

determiningTheFunctionDomain
32(n-10)+740

We multiply parentheses

32n-320+740

We add all the numbers together, and all the variables

32n+420

Back to the equation:

-(32n+420)



We get rid of parentheses

-32n-420=0

We move all terms containing n to the left, all other terms to the right

-32n=420

n=420/-32

n=-13+1/8

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