0=8(1+3b)-4(-1+3b)

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Solution for 0=8(1+3b)-4(-1+3b) equation: 



0=8(1+3b)-4(-1+3b)

We move all terms to the left:

0-(8(1+3b)-4(-1+3b))=0

We add all the numbers together, and all the variables

-(8(3b+1)-4(3b-1))+0=0

We add all the numbers together, and all the variables

-(8(3b+1)-4(3b-1))=0



We calculate terms in parentheses: -(8(3b+1)-4(3b-1)), so:

8(3b+1)-4(3b-1)

We multiply parentheses

24b-12b+8+4

We add all the numbers together, and all the variables

12b+12

Back to the equation:

-(12b+12)



We get rid of parentheses

-12b-12=0

We move all terms containing b to the left, all other terms to the right

-12b=12

b=12/-12

b=-1

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