0=8/3x-1x

Solution for 0=8/3x-1x equation:

0=8/3x-1x

We move all terms to the left:

0-(8/3x-1x)=0


Domain of the equation: 3x-1x)!=0

x∈R


We add all the numbers together, and all the variables

-(-1x+8/3x)+0=0

We add all the numbers together, and all the variables

-(-1x+8/3x)=0

We get rid of parentheses

1x-8/3x=0

We multiply all the terms by the denominator


1x*3x-8=0

Wy multiply elements

3x^2-8=0

a = 3; b = 0; c = -8;
Δ = b2-4ac
Δ = 02-4·3·(-8)
Δ = 96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{96}=\sqrt{16*6}=\sqrt{16}*\sqrt{6}=4\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{6}}{2*3}=\frac{0-4\sqrt{6}}{6}
=-\frac{4\sqrt{6}}{6}
=-\frac{2\sqrt{6}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{6}}{2*3}=\frac{0+4\sqrt{6}}{6}
=\frac{4\sqrt{6}}{6}
=\frac{2\sqrt{6}}{3}
$