0=80(8+x)(8-x)

Solution for 0=80(8+x)(8-x) equation:

0=80(8+x)(8-x)

We move all terms to the left:

0-(80(8+x)(8-x))=0

We add all the numbers together, and all the variables

-(80(x+8)(-1x+8))+0=0

We add all the numbers together, and all the variables

-(80(x+8)(-1x+8))=0

We multiply parentheses ..

-(80(-1x^2+8x-8x+64))=0


We calculate terms in parentheses: -(80(-1x^2+8x-8x+64)), so:

80(-1x^2+8x-8x+64)

We multiply parentheses

-80x^2+640x-640x+5120

We add all the numbers together, and all the variables

-80x^2+5120

Back to the equation:

-(-80x^2+5120)


We get rid of parentheses

80x^2-5120=0

a = 80; b = 0; c = -5120;
Δ = b2-4ac
Δ = 02-4·80·(-5120)
Δ = 1638400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1638400}=1280$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-1280}{2*80}=\frac{-1280}{160}
=-8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+1280}{2*80}=\frac{1280}{160}
=8
$