0=8i(9+4i)

Solution for 0=8i(9+4i) equation:

0=8i(9+4i)

We move all terms to the left:

0-(8i(9+4i))=0

We add all the numbers together, and all the variables

-(8i(4i+9))+0=0

We add all the numbers together, and all the variables

-(8i(4i+9))=0


We calculate terms in parentheses: -(8i(4i+9)), so:

8i(4i+9)

We multiply parentheses

32i^2+72i

Back to the equation:

-(32i^2+72i)


We get rid of parentheses

-32i^2-72i=0

a = -32; b = -72; c = 0;
Δ = b2-4ac
Δ = -722-4·(-32)·0
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-72}{2*-32}=\frac{0}{-64}
=0
$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+72}{2*-32}=\frac{144}{-64}
=-2+1/4
$