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0=8x^2+10x-6
We move all terms to the left:
0-(8x^2+10x-6)=0
We add all the numbers together, and all the variables
-(8x^2+10x-6)=0
We get rid of parentheses
-8x^2-10x+6=0
a = -8; b = -10; c = +6;
Δ = b2-4ac
Δ = -102-4·(-8)·6
Δ = 292
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{292}=\sqrt{4*73}=\sqrt{4}*\sqrt{73}=2\sqrt{73}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{73}}{2*-8}=\frac{10-2\sqrt{73}}{-16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{73}}{2*-8}=\frac{10+2\sqrt{73}}{-16} $
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