0=9(7+k)+(6k+3)9

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Solution for 0=9(7+k)+(6k+3)9 equation: 



0=9(7+k)+(6k+3)9

We move all terms to the left:

0-(9(7+k)+(6k+3)9)=0

We add all the numbers together, and all the variables

-(9(k+7)+(6k+3)9)+0=0

We add all the numbers together, and all the variables

-(9(k+7)+(6k+3)9)=0



We calculate terms in parentheses: -(9(k+7)+(6k+3)9), so:

9(k+7)+(6k+3)9

We multiply parentheses

9k+54k+63+27

We add all the numbers together, and all the variables

63k+90

Back to the equation:

-(63k+90)



We get rid of parentheses

-63k-90=0

We move all terms containing k to the left, all other terms to the right

-63k=90

k=90/-63

k=-1+3/7

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