0=9x2+19x+10

Solution for 0=9x2+19x+10 equation:

0=9x^2+19x+10

We move all terms to the left:

0-(9x^2+19x+10)=0

We add all the numbers together, and all the variables

-(9x^2+19x+10)=0

We get rid of parentheses

-9x^2-19x-10=0

a = -9; b = -19; c = -10;
Δ = b2-4ac
Δ = -192-4·(-9)·(-10)
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-1}{2*-9}=\frac{18}{-18}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+1}{2*-9}=\frac{20}{-18}
=-1+1/9
$