0=a(12-36a)

Solution for 0=a(12-36a) equation:

0=a(12-36a)

We move all terms to the left:

0-(a(12-36a))=0

We add all the numbers together, and all the variables

-(a(-36a+12))+0=0

We add all the numbers together, and all the variables

-(a(-36a+12))=0


We calculate terms in parentheses: -(a(-36a+12)), so:

a(-36a+12)

We multiply parentheses

-36a^2+12a

Back to the equation:

-(-36a^2+12a)


We get rid of parentheses

36a^2-12a=0

a = 36; b = -12; c = 0;
Δ = b2-4ac
Δ = -122-4·36·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-12}{2*36}=\frac{0}{72}
=0
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+12}{2*36}=\frac{24}{72}
=1/3
$