0=ln(1+3x)-x

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Solution for 0=ln(1+3x)-x equation:


Simplifying
0 = ln(1 + 3x) + -1x
0 = (1 * ln + 3x * ln) + -1x
0 = (1ln + 3lnx) + -1x

Solving
0 = 1ln + 3lnx + -1x

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Add '-1ln' to each side of the equation.
0 + -1ln = 1ln + 3lnx + -1ln + -1x
Remove the zero:
-1ln = 1ln + 3lnx + -1ln + -1x

Reorder the terms:
-1ln = 1ln + -1ln + 3lnx + -1x

Combine like terms: 1ln + -1ln = 0
-1ln = 0 + 3lnx + -1x
-1ln = 3lnx + -1x

Add '-3lnx' to each side of the equation.
-1ln + -3lnx = 3lnx + -3lnx + -1x

Combine like terms: 3lnx + -3lnx = 0
-1ln + -3lnx = 0 + -1x
-1ln + -3lnx = -1x

Combine like terms: -1x + x = 0
-1ln + -3lnx + x = 0

The solution to this equation could not be determined.

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