0=ln(x+2)+ln(x-2)

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Solution for 0=ln(x+2)+ln(x-2) equation:


Simplifying
0 = ln(x + 2) + ln(x + -2)

Reorder the terms:
0 = ln(2 + x) + ln(x + -2)
0 = (2 * ln + x * ln) + ln(x + -2)
0 = (2ln + lnx) + ln(x + -2)

Reorder the terms:
0 = 2ln + lnx + ln(-2 + x)
0 = 2ln + lnx + (-2 * ln + x * ln)
0 = 2ln + lnx + (-2ln + lnx)

Reorder the terms:
0 = 2ln + -2ln + lnx + lnx

Combine like terms: 2ln + -2ln = 0
0 = 0 + lnx + lnx
0 = lnx + lnx

Combine like terms: lnx + lnx = 2lnx
0 = 2lnx

Solving
0 = 2lnx

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Add '-2lnx' to each side of the equation.
0 + -2lnx = 2lnx + -2lnx
Remove the zero:
-2lnx = 2lnx + -2lnx

Combine like terms: 2lnx + -2lnx = 0
-2lnx = 0

Divide each side by '-2'.
lnx = 0

Simplifying
lnx = 0

The solution to this equation could not be determined.

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