0=ln(x-4)+2

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Solution for 0=ln(x-4)+2 equation:


Simplifying
0 = ln(x + -4) + 2

Reorder the terms:
0 = ln(-4 + x) + 2
0 = (-4 * ln + x * ln) + 2
0 = (-4ln + lnx) + 2

Reorder the terms:
0 = 2 + -4ln + lnx

Solving
0 = 2 + -4ln + lnx

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Add '4ln' to each side of the equation.
0 + 4ln = 2 + -4ln + 4ln + lnx
Remove the zero:
4ln = 2 + -4ln + 4ln + lnx

Combine like terms: -4ln + 4ln = 0
4ln = 2 + 0 + lnx
4ln = 2 + lnx

Add '-1lnx' to each side of the equation.
4ln + -1lnx = 2 + lnx + -1lnx

Combine like terms: lnx + -1lnx = 0
4ln + -1lnx = 2 + 0
4ln + -1lnx = 2

Reorder the terms:
-2 + 4ln + -1lnx = 2 + -2

Combine like terms: 2 + -2 = 0
-2 + 4ln + -1lnx = 0

The solution to this equation could not be determined.

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