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0=n(2n+3)(3n-2)
We move all terms to the left:
0-(n(2n+3)(3n-2))=0
We add all the numbers together, and all the variables
-(n(2n+3)(3n-2))=0
We multiply parentheses ..
-(n(+6n^2-4n+9n-6))=0
We calculate terms in parentheses: -(n(+6n^2-4n+9n-6)), so:
n(+6n^2-4n+9n-6)
We multiply parentheses
6n^3-4n^2+9n^2-6n
We do not support enpression: n^3
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