0=n2+n-110

Solution for 0=n2+n-110 equation:

0=n2+n-110

We move all terms to the left:

0-(n2+n-110)=0

We add all the numbers together, and all the variables

-(+n^2+n-110)+0=0

We add all the numbers together, and all the variables

-(+n^2+n-110)=0

We get rid of parentheses

-n^2-n+110=0

We add all the numbers together, and all the variables

-1n^2-1n+110=0

a = -1; b = -1; c = +110;
Δ = b2-4ac
Δ = -12-4·(-1)·110
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-21}{2*-1}=\frac{-20}{-2}
=+10
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+21}{2*-1}=\frac{22}{-2}
=-11
$