0=t(40-16t)

Solution for 0=t(40-16t) equation:

0=t(40-16t)

We move all terms to the left:

0-(t(40-16t))=0

We add all the numbers together, and all the variables

-(t(-16t+40))+0=0

We add all the numbers together, and all the variables

-(t(-16t+40))=0


We calculate terms in parentheses: -(t(-16t+40)), so:

t(-16t+40)

We multiply parentheses

-16t^2+40t

Back to the equation:

-(-16t^2+40t)


We get rid of parentheses

16t^2-40t=0

a = 16; b = -40; c = 0;
Δ = b2-4ac
Δ = -402-4·16·0
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-40}{2*16}=\frac{0}{32}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+40}{2*16}=\frac{80}{32}
=2+1/2
$