0=w2+4w-450

Solution for 0=w2+4w-450 equation:

0=w2+4w-450

We move all terms to the left:

0-(w2+4w-450)=0

We add all the numbers together, and all the variables

-(+w^2+4w-450)+0=0

We add all the numbers together, and all the variables

-(+w^2+4w-450)=0

We get rid of parentheses

-w^2-4w+450=0

We add all the numbers together, and all the variables

-1w^2-4w+450=0

a = -1; b = -4; c = +450;
Δ = b2-4ac
Δ = -42-4·(-1)·450
Δ = 1816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1816}=\sqrt{4*454}=\sqrt{4}*\sqrt{454}=2\sqrt{454}$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-2\sqrt{454}}{2*-1}=\frac{4-2\sqrt{454}}{-2}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+2\sqrt{454}}{2*-1}=\frac{4+2\sqrt{454}}{-2}
$