0=w2+8w+7

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Solution for 0=w2+8w+7 equation:



0=w2+8w+7
We move all terms to the left:
0-(w2+8w+7)=0
We add all the numbers together, and all the variables
-(+w^2+8w+7)+0=0
We add all the numbers together, and all the variables
-(+w^2+8w+7)=0
We get rid of parentheses
-w^2-8w-7=0
We add all the numbers together, and all the variables
-1w^2-8w-7=0
a = -1; b = -8; c = -7;
Δ = b2-4ac
Δ = -82-4·(-1)·(-7)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-6}{2*-1}=\frac{2}{-2} =-1 $
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+6}{2*-1}=\frac{14}{-2} =-7 $

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