0=x(300-25x)

Solution for 0=x(300-25x) equation:

0=x(300-25x)

We move all terms to the left:

0-(x(300-25x))=0

We add all the numbers together, and all the variables

-(x(-25x+300))+0=0

We add all the numbers together, and all the variables

-(x(-25x+300))=0


We calculate terms in parentheses: -(x(-25x+300)), so:

x(-25x+300)

We multiply parentheses

-25x^2+300x

Back to the equation:

-(-25x^2+300x)


We get rid of parentheses

25x^2-300x=0

a = 25; b = -300; c = 0;
Δ = b2-4ac
Δ = -3002-4·25·0
Δ = 90000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{90000}=300$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-300)-300}{2*25}=\frac{0}{50}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-300)+300}{2*25}=\frac{600}{50}
=12
$