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0=x(44-2x)
We move all terms to the left:
0-(x(44-2x))=0
We add all the numbers together, and all the variables
-(x(-2x+44))+0=0
We add all the numbers together, and all the variables
-(x(-2x+44))=0
We calculate terms in parentheses: -(x(-2x+44)), so:We get rid of parentheses
x(-2x+44)
We multiply parentheses
-2x^2+44x
Back to the equation:
-(-2x^2+44x)
2x^2-44x=0
a = 2; b = -44; c = 0;
Δ = b2-4ac
Δ = -442-4·2·0
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-44}{2*2}=\frac{0}{4} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+44}{2*2}=\frac{88}{4} =22 $
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