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0=x(6x-7)
We move all terms to the left:
0-(x(6x-7))=0
We add all the numbers together, and all the variables
-(x(6x-7))=0
We calculate terms in parentheses: -(x(6x-7)), so:We get rid of parentheses
x(6x-7)
We multiply parentheses
6x^2-7x
Back to the equation:
-(6x^2-7x)
-6x^2+7x=0
a = -6; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·(-6)·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*-6}=\frac{-14}{-12} =1+1/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*-6}=\frac{0}{-12} =0 $
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