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0=x(x+5)(x-7)
We move all terms to the left:
0-(x(x+5)(x-7))=0
We add all the numbers together, and all the variables
-(x(x+5)(x-7))=0
We multiply parentheses ..
-(x(+x^2-7x+5x-35))=0
We calculate terms in parentheses: -(x(+x^2-7x+5x-35)), so:
x(+x^2-7x+5x-35)
We multiply parentheses
x^3-7x^2+5x^2-35x
We do not support expression: x^3
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