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0=x(x+9)
We move all terms to the left:
0-(x(x+9))=0
We add all the numbers together, and all the variables
-(x(x+9))=0
We calculate terms in parentheses: -(x(x+9)), so:We get rid of parentheses
x(x+9)
We multiply parentheses
x^2+9x
Back to the equation:
-(x^2+9x)
-x^2-9x=0
We add all the numbers together, and all the variables
-1x^2-9x=0
a = -1; b = -9; c = 0;
Δ = b2-4ac
Δ = -92-4·(-1)·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-9}{2*-1}=\frac{0}{-2} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+9}{2*-1}=\frac{18}{-2} =-9 $
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