0=x(x-3)

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Solution for 0=x(x-3) equation:



0=x(x-3)
We move all terms to the left:
0-(x(x-3))=0
We add all the numbers together, and all the variables
-(x(x-3))=0
We calculate terms in parentheses: -(x(x-3)), so:
x(x-3)
We multiply parentheses
x^2-3x
Back to the equation:
-(x^2-3x)
We get rid of parentheses
-x^2+3x=0
We add all the numbers together, and all the variables
-1x^2+3x=0
a = -1; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·(-1)·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*-1}=\frac{-6}{-2} =+3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*-1}=\frac{0}{-2} =0 $

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