0=x2+11x+29

Solution for 0=x2+11x+29 equation:

0=x2+11x+29

We move all terms to the left:

0-(x2+11x+29)=0

We add all the numbers together, and all the variables

-(+x^2+11x+29)+0=0

We add all the numbers together, and all the variables

-(+x^2+11x+29)=0

We get rid of parentheses

-x^2-11x-29=0

We add all the numbers together, and all the variables

-1x^2-11x-29=0

a = -1; b = -11; c = -29;
Δ = b2-4ac
Δ = -112-4·(-1)·(-29)
Δ = 5
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{5}}{2*-1}=\frac{11-\sqrt{5}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{5}}{2*-1}=\frac{11+\sqrt{5}}{-2}
$