0=x2+12x+36

Solution for 0=x2+12x+36 equation:

0=x2+12x+36

We move all terms to the left:

0-(x2+12x+36)=0

We add all the numbers together, and all the variables

-(+x^2+12x+36)+0=0

We add all the numbers together, and all the variables

-(+x^2+12x+36)=0

We get rid of parentheses

-x^2-12x-36=0

We add all the numbers together, and all the variables

-1x^2-12x-36=0

a = -1; b = -12; c = -36;
Δ = b2-4ac
Δ = -122-4·(-1)·(-36)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{12}{-2}=-6$