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0=x2+13x-103
We move all terms to the left:
0-(x2+13x-103)=0
We add all the numbers together, and all the variables
-(+x^2+13x-103)+0=0
We add all the numbers together, and all the variables
-(+x^2+13x-103)=0
We get rid of parentheses
-x^2-13x+103=0
We add all the numbers together, and all the variables
-1x^2-13x+103=0
a = -1; b = -13; c = +103;
Δ = b2-4ac
Δ = -132-4·(-1)·103
Δ = 581
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{581}}{2*-1}=\frac{13-\sqrt{581}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{581}}{2*-1}=\frac{13+\sqrt{581}}{-2} $
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