0=x2+13x-103

Solution for 0=x2+13x-103 equation:

0=x2+13x-103

We move all terms to the left:

0-(x2+13x-103)=0

We add all the numbers together, and all the variables

-(+x^2+13x-103)+0=0

We add all the numbers together, and all the variables

-(+x^2+13x-103)=0

We get rid of parentheses

-x^2-13x+103=0

We add all the numbers together, and all the variables

-1x^2-13x+103=0

a = -1; b = -13; c = +103;
Δ = b2-4ac
Δ = -132-4·(-1)·103
Δ = 581
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{581}}{2*-1}=\frac{13-\sqrt{581}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{581}}{2*-1}=\frac{13+\sqrt{581}}{-2}
$