0=x2+14x+40

Solution for 0=x2+14x+40 equation:

0=x2+14x+40

We move all terms to the left:

0-(x2+14x+40)=0

We add all the numbers together, and all the variables

-(+x^2+14x+40)+0=0

We add all the numbers together, and all the variables

-(+x^2+14x+40)=0

We get rid of parentheses

-x^2-14x-40=0

We add all the numbers together, and all the variables

-1x^2-14x-40=0

a = -1; b = -14; c = -40;
Δ = b2-4ac
Δ = -142-4·(-1)·(-40)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-6}{2*-1}=\frac{8}{-2}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+6}{2*-1}=\frac{20}{-2}
=-10
$