0=x2+4x-480

Solution for 0=x2+4x-480 equation:

0=x2+4x-480

We move all terms to the left:

0-(x2+4x-480)=0

We add all the numbers together, and all the variables

-(+x^2+4x-480)+0=0

We add all the numbers together, and all the variables

-(+x^2+4x-480)=0

We get rid of parentheses

-x^2-4x+480=0

We add all the numbers together, and all the variables

-1x^2-4x+480=0

a = -1; b = -4; c = +480;
Δ = b2-4ac
Δ = -42-4·(-1)·480
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-44}{2*-1}=\frac{-40}{-2}
=+20
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+44}{2*-1}=\frac{48}{-2}
=-24
$