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0=x2+7x-18
We move all terms to the left:
0-(x2+7x-18)=0
We add all the numbers together, and all the variables
-(+x^2+7x-18)+0=0
We add all the numbers together, and all the variables
-(+x^2+7x-18)=0
We get rid of parentheses
-x^2-7x+18=0
We add all the numbers together, and all the variables
-1x^2-7x+18=0
a = -1; b = -7; c = +18;
Δ = b2-4ac
Δ = -72-4·(-1)·18
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-11}{2*-1}=\frac{-4}{-2} =+2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+11}{2*-1}=\frac{18}{-2} =-9 $
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