0=y2+0.9028y-0.1733

Solution for 0=y2+0.9028y-0.1733 equation:

0=y2+0.9028y-0.1733

We move all terms to the left:

0-(y2+0.9028y-0.1733)=0

We add all the numbers together, and all the variables

-(+y^2+0.9028y-0.1733)+0=0

We add all the numbers together, and all the variables

-(+y^2+0.9028y-0.1733)=0

We get rid of parentheses

-y^2-0.9028y+0.1733=0

We add all the numbers together, and all the variables

-1y^2-0.9028y+0.1733=0

a = -1; b = -0.9028; c = +0.1733;
Δ = b2-4ac
Δ = -0.90282-4·(-1)·0.1733
Δ = 1.50824784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.9028)-\sqrt{1.50824784}}{2*-1}=\frac{0.9028-\sqrt{1.50824784}}{-2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.9028)+\sqrt{1.50824784}}{2*-1}=\frac{0.9028+\sqrt{1.50824784}}{-2}
$